Active Calculus · 12: Appendices

12.1: A- Short Table of Integrals

Appendix A A Short Table of Integrals
a. ∫dua2+u2=1aarctan⁡(ua)+C\int \frac{d u}{a^2+u^2}=\frac{1}{a} \arctan \left(\frac{u}{a}\right)+C

b. ∫duu2±a2=ln⁡∣u+u2±a2∣+C\int \frac{d u}{\sqrt{u^2 \pm a^2}}=\ln \left|u+\sqrt{u^2 \pm a^2}\right|+C

c. ∫u2±a2du=u2u2±a2±a22ln⁡∣u+u2±a2∣+C\int \sqrt{u^2 \pm a^2} d u=\frac{u}{2} \sqrt{u^2 \pm a^2} \pm \frac{a^2}{2} \ln \left|u+\sqrt{u^2 \pm a^2}\right|+C

d. ∫u2duu2±a2=u2u2±a2∓a22ln⁡∣u+u2±a2∣+C\int \frac{u^2 d u}{\sqrt{u^2 \pm a^2}}=\frac{u}{2} \sqrt{u^2 \pm a^2} \mp \frac{a^2}{2} \ln \left|u+\sqrt{u^2 \pm a^2}\right|+C

e. ∫duuu2+a2=−1aln⁡∣a+u2+a2u∣+C\int \frac{d u}{u \sqrt{u^2+a^2}}=-\frac{1}{a} \ln \left|\frac{a+\sqrt{u^2+a^2}}{u}\right|+C

f. ∫duuu2−a2=1aarcsec⁡(ua)+C\int \frac{d u}{u \sqrt{u^2-a^2}}=\frac{1}{a} \operatorname{arcsec}\left(\frac{u}{a}\right)+C

g. ∫dua2−u2=arcsin⁡(ua)+C\int \frac{d u}{\sqrt{a^2-u^2}}=\arcsin \left(\frac{u}{a}\right)+C

h. ∫a2−u2du=u2a2−u2+a22arcsin⁡(ua)+C\int \sqrt{a^2-u^2} d u=\frac{u}{2} \sqrt{a^2-u^2}+\frac{a^2}{2} \arcsin \left(\frac{u}{a}\right)+C

i. ∫u2a2−u2du=−u2a2−u2+a22arcsin⁡(ua)+C\int \frac{u^2}{\sqrt{a^2-u^2}} d u=-\frac{u}{2} \sqrt{a^2-u^2}+\frac{a^2}{2} \arcsin \left(\frac{u}{a}\right)+C

j. ∫duua2−u2=−1aln⁡∣a+a2−u2u∣+C\int \frac{d u}{u \sqrt{a^2-u^2}}=-\frac{1}{a} \ln \left|\frac{a+\sqrt{a^2-u^2}}{u}\right|+C

k. ∫duu2a2−u2=−a2−u2a2u+C\int \frac{d u}{u^2 \sqrt{a^2-u^2}}=-\frac{\sqrt{a^2-u^2}}{a^2 u}+C

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This page titled 12.1: A- Short Table of Integrals was last modified on Wed, 09 Nov 2022 19:59:49 GMT and is shared under a CC BY-SA 4.0 license and was authored, remixed, and/or curated by Matthew Boelkins, David Austin, and Steven Schlicker ( ScholarWorks @Grand Valley State University ) .

Source: https://math.libretexts.org/Bookshelves/Calculus/Active_Calculus_(Boelkins_et_al.)/12%3A_Appendices/12.01%3A_A-_Short_Table_of_Integrals

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